Title credit: u/AngelicDimsum

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[–] 8 points 2 months ago (1 child)
  • [–] 14 points 2 months ago (1 child)

    Each number is represented as a circle which contains the numbers below it.

    4 contains 1 2 3 and 4 (the set contains itself)

    Within the containing circle: Top left is a single circle, so it is 1. Top right is 2, so its a circle with another circle in it. Bottom left is three, so it contains both the previous symbols for 1 and a 2. And the final number is 4, so it has all the previous circle diagrams in it.

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  • [–] 10 points 2 months ago (1 child)

    I may be missing something but why would 4 contain 4 when 3 doesn't contain 3 and 2 doesn't contain 2?

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  • [–] 18 points 2 months ago (1 child)

    Excellent question, the answer is you've now reached the end of my understanding of set theory

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  • [–] 13 points 2 months ago (2 children)

    I think you were off by one? I think the single circle is more like zero, then the top right is 1, bottom left is 2, bottom right is 3, and the whole thing is 4.

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  • [–] 7 points 2 months ago

    Sometimes I think that after I die, I'm gonna confront whatever higher power type of consciousness that was in charge of this reality and I'm gonna ask "What the heck was the purpose of all that?"

    And the answer is gonna be, "It was actually an off by one error" and I feel like it's gonna actually make sense at that point.

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  • [–] 6 points 2 months ago
    [–] 4 points 2 months ago
    [–] 3 points 2 months ago

    Now express -1/12 as a summation of null sets? It'd take a bit.

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  • [–] 0 points 2 months ago (2 children)

    Isn't four {{{{{}}}}}? The diagram shows more than that.

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  • [–] 2 points 2 months ago (1 child)

    It could be defined that way. But your set is in a way more difficult to resolve as it has only one element. In the diagram the number of elements (4 sets) of the set is equal to the number 4 i.e. a set defines a number by simply counting its elements.

    There are probably some other nice properties if you define it that way.

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