SpaceflightMemes

[–] AppleTea@lemmy.zip 14 points 2 months ago (1 child)

Each number is represented as a circle which contains the numbers below it.

4 contains 1 2 3 and 4 (the set contains itself)

Within the containing circle: Top left is a single circle, so it is 1. Top right is 2, so its a circle with another circle in it. Bottom left is three, so it contains both the previous symbols for 1 and a 2. And the final number is 4, so it has all the previous circle diagrams in it.

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[–] Lodespawn@aussie.zone 10 points 2 months ago (1 child)

I may be missing something but why would 4 contain 4 when 3 doesn't contain 3 and 2 doesn't contain 2?

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[–] AppleTea@lemmy.zip 18 points 2 months ago (1 child)

Excellent question, the answer is you've now reached the end of my understanding of set theory

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[–] agamemnonymous@sh.itjust.works 13 points 2 months ago (2 children)

I think you were off by one? I think the single circle is more like zero, then the top right is 1, bottom left is 2, bottom right is 3, and the whole thing is 4.

hideshow 4 child comments

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[–] topherclay@lemmy.world 7 points 2 months ago

Sometimes I think that after I die, I'm gonna confront whatever higher power type of consciousness that was in charge of this reality and I'm gonna ask "What the heck was the purpose of all that?"

And the answer is gonna be, "It was actually an off by one error" and I feel like it's gonna actually make sense at that point.

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[–] Lodespawn@aussie.zone 5 points 2 months ago

That would make sense because the fist circle is a null set with nothing in it