▲ 1429 ▼ Golang be like (i.imgur.com) submitted 2 years ago by mycroftholmess@lemm.ee to c/programmer_humor@programming.dev 137 comments fedilink hide all child comments
[+] Draces@lemm.ee 121 points 2 years ago* (last edited 2 years ago) (4 children) [deleted] permalink fedilink source hideshow 8 child comments replies: [–] devfuuu@lemmy.world 33 points 2 years ago (1 child) People are scared of monads and think this is better. permalink fedilink source parent hideshow 2 child comments replies: [–] serenity@lemmy.world 7 points 2 years ago (3 children) My brain is too smooth to imagine a solution to this using monads. Mind sharing what you got with the class? permalink fedilink source parent hideshow 6 child comments replies: [–] nick@campfyre.nickwebster.dev 12 points 2 years ago* (1 child) Having a Result[T, Err] monad that could represent either the data from a successful operation or an error. This can be generalised to the Either[A, B] monad too. permalink fedilink source parent hideshow 2 child comments replies: [–] serenity@lemmy.world 2 points 2 years ago* (3 children) Either[A, B] monad Wait, that's all monads are? some generic class Either ? permalink fedilink source parent hideshow 6 child comments replies: [–] oessessnex@programming.dev 11 points 2 years ago* (last edited 2 years ago) Nope. Monads enable you to redefine how statements work. Let's say you have a program and use an Error[T] data type which can either be Ok {Value: T} or Error: var a = new Ok {Value = 1}; var b = foo(); return new Ok {Value = (a + b)}; Each statement has the following form: var a = expr; rest You first evaluate the "expr" part and bind/store the result in variable a, and evaluate the "rest" of the program. You could represent the same thing using an anonymous function you evaluate right away: (a => rest)(expr); In a normal statement you just pass the result of "expr" to the function directly. The monad allows you to redefine that part. You instead write: bind((a => rest), expr); Here "bind" redefines how the result of expr is passed to the anonymous function. If you implement bind as: B bind(Func[A, B] f, A result_expr) { return f(result_expr); } Then you get normal statements. If you implement bind as: Error[B] bind(Func[A, Error[B]] f, Error[A] result_expr) { switch (result_expr) { case Ok { Value: var a}: return f(a); case Error: return Error; } } You get statements with error handling. So in an above example if the result of foo() is Error, the result of the statement is Error and the rest of the program is not evaluated. Otherwise, if the result of foo() is Ok {Value = 3}, you pass 3 to the rest of the program and you get a final result Ok {Value = 4}. So the whole idea is that you hide the if Error part by redefining how the statements are interpreted. permalink fedilink source parent [–] barsoap@lemm.ee 4 points 2 years ago* (last edited 2 years ago) "Some generic class" with specific methods and laws, Monads are an algebraic structure and you want those laws included same as if you enable some type to use + you want to have a 0 somewhere and x + 0 == x to hold. Like "foo" + "" == "foo" in the case of strings, just as an example. In Rust, Result and Option actually are monads. Let's take Option as example: pure x is Some(x) a >>= b is a.and_then(b) Then we have: Left identity: Some(x).and_then(f) ≡ f(x) Right identity: x.and_then(Some) ≡ x Associativity: m.and_then(g).and_then(h) ≡ m.and_then(|x| g(x).and_then(h)) Why those laws? Because following them avoids surprises like x + 0 /= x. Rust's type system isn't powerful enough to have a Monad trait (lack of HKTs) hence why you can't write code that works with any type that implements that kind of interface. Result names >>= and_then, just like Option does so the code reads the same but you'll have to choose between Option or Result in the type signature, the code can't be properly generic over it. permalink fedilink source parent [–] m_f@midwest.social 3 points 2 years ago This is the best explanation I've ever seen of monads: https://www.adit.io/posts/2013-04-17-functors,_applicatives,_and_monads_in_pictures.html For some reason, you'll find a lot of really bad explanations of monads, like "programmable semi-colons". Ignore those, and check out the link. permalink fedilink source parent [–] psilocybin@discuss.tchncs.de 5 points 2 years ago* (last edited 2 years ago) Someone else and not an expert. But Maybe types are implemented with Monads, Maybe is a common monad. Its how rust does error handling for example, you have to test a return value for "something or nothing" but you can pass the monadic value and handle the error later, in go you have to handle the error explicitly (almost) all the time. permalink fedilink source parent [–] Nevoic@lemmy.world 2 points 2 years ago* (last edited 2 years ago) Here's an example (first in Haskell then in Go), lets say you have some types/functions: type Possible a = Either String a data User = User { name :: String, age :: Int } validateName :: String -> Possible String validateAge :: Int -> Possible Int then you can make mkValidUser :: String -> Int -> Possible User mkValidUser name age = do validatedName ← validateName name validatedAge ← validateAge age pure $ User validatedName validatedAge for some reason <- in lemmy shows up as <- inside code blocks, so I used the left arrow unicode in the above instead in Go you'd have these (no Possible type alias, Go can't do generic type aliases yet, there's an open issue for it) type User struct { Name string; Age int } func validateName(name string) (string, error) func validateAge(age int) (int, error) and with them you'd make: func mkValidUser(name string, age int) (*User, error) { validatedName, err = validateName(name) if err != nil { return nil, err } validatedAge, err = validateAge(age) if err != nil { return nil, err } return User(Name: validatedName, Age: validatedAge), nil } In the Haskell, the fact that Either is a monad is saving you from a lot of boilerplate. You don't have to explicitly handle the Left/error case, if any of the Eithers end up being a Left value then it'll correctly "short-circuit" and the function will evaluate to that Left value. Without using the fact that it's a functor/monad (e.g you have no access to fmap/>>=/do syntax), you'd end up with code that has a similar amount of boilerplate to the Go code (notice we have to handle each Left case now): mkValidUser :: String -> Int -> Possible User mkValidUser name age = case (validatedName name, validateAge age) of (Left nameErr, _) => Left nameErr (_, Left ageErr) => Left ageErr (Right validatedName, Right validatedAge) => Right $ User validatedName validatedAge permalink fedilink source parent [–] arc@lemm.ee 20 points 2 years ago (1 child) Swift and Rust have a far more elegant solution. Swift has a pseudo throw / try-catch, while Rust has a Result<> and if you want to throw it up the chain you can use a ? notation instead of cluttering the code with error checking. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 6 points 2 years ago (3 children) The exception handling question mark, spelled ? and abbreviated and pronounced eh?, is a half-arsed copy of monadic error handling. Rust devs really wanted the syntax without introducing HKTs, and admittedly you can't do foo()?.bar()?.baz()? in Haskell so it's only theoretical purity which is half-arsed, not ergonomics. permalink fedilink source parent hideshow 6 child comments replies: [–] m_f@midwest.social 1 point 2 years ago (1 child) It's not a half-arsed copy, it's borrowing a limited subset of HKT for a language with very different goals. Haskell can afford a lot of luxuries that Rust can't. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago It's a specialised syntax transformation that has nothing to do with HKTs, or the type system in general. Also HKTs aren't off the table it's just that their theory isn't exactly trivial in face of the rest of Rust's type system but we already have GATs. It actually wouldn't be hard writing a macro implementing do-notation that desugars to and_then calls on a particular type to get some kind of generic code (though of course monomorphised), but of course that would be circumventing the type system. Anyhow my point stands that how Rust currently does it is imitating all that Haskell goodness on a practical everyday coding level but without having (yet) to solve the hard problem of how to do it without special-cased syntax sugar. With proper monads we e.g. wouldn't need to have separate syntax for async and ? permalink fedilink source parent [–] Nevoic@lemmy.world 1 point 2 years ago* (1 child) Note: Lemmy code blocks don't play nice with some symbols, specifically < and & in the following code examples This isn't a language level issue really though, Haskell can be equally ergonomic. The weird thing about ?. is that it's actually overloaded, it can mean: call a function on A? that returns B? call a function on A? that returns B you'd end up with B? in either case Say you have these functions toInt :: String -> Maybe Int double :: Int -> Int isValid :: Int -> Maybe Int and you want to construct the following using these 3 functions fn :: Maybe String -> Maybe Int in a Rust-type syntax, you'd call str?.toInt()?.double()?.isValid() in Haskell you'd have two different operators here str >>= toInt <&> double >>= isValid however you can define this type class class Chainable f a b fb where (?.) :: f a -> (a -> fb) -> f b instance Functor f => Chainable f a b b where (?.) = (<&>) instance Monad m => Chainable m a b (m b) where (?.) = (>>=) and then get roughly the same syntax as rust without introducing a new language feature str ?. toInt ?. double ?. isValid though this is more general than just Maybes (it works with any functor/monad), and maybe you wouldn't want it to be. In that case you'd do this class Chainable a b fb where (?.) :: Maybe a -> (a -> fb) -> Maybe b instance Chainable a b b where (?.) = (<&>) instance Chainable a b (Maybe b) where (?.) = (>>=) restricting it to only maybes could also theoretically help type inference. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago* (last edited 2 years ago) I was thinking along the lines of "you can't easily get at the wrapped type". To get at b instead of Maybe b you need to either use do-notation or lambdas (which do-notation is supposed to eliminate because they're awkward in a monadic context) whereas Rust will gladly hand you that b in the middle of an expression, and doesn't force you to name the point. Or to give a concrete example, if foo()? {...} is rather awkward in Haskell, you end up writing things like foo x y = bar >>= baz x y where baz x y True = x baz x y False = y , though of course baz is completely generic and can be factored out. I think I called it "cap" in my Haskell days, for "consequent-alternative-predicate". Flattening Functors and Monads syntax-wise is neat but it's not getting you all the way. But it's the Haskell way: Instead of macros, use tons upon tons of trivial functions :) permalink fedilink source parent [–] arc@lemm.ee 0 points 2 years ago You can say it's half-arsed if you like, but it's still vastly more convenient to write than if err != nil all over the place permalink fedilink source parent [–] christophski@feddit.uk 7 points 2 years ago (4 children) Can anybody explain the rationale behind this? permalink fedilink source parent hideshow 8 child comments replies: [–] fkn@lemmy.world 14 points 2 years ago (2 children) Exceptions don't exists and ask errors must be handled at every level. It's infuriating. permalink fedilink source parent hideshow 4 child comments replies: [–] planish@sh.itjust.works 4 points 2 years ago I actually kind of like the error handling. Code should explain why something was a problem, not just where it was a problem. You get a huge string of "couldn't foobar the baz: target baz was not greebleable: no greeble provider named fizzbuzz", and while the strings are long as hell they are much better explanations for a problem than a stack trace is. permalink fedilink source parent [–] msage@programming.dev -2 points 2 years ago (1 child) Hahaha, fuck no, I've dealt with exception-less code enough in my life, kthxbye permalink fedilink source parent hideshow 2 child comments replies: [–] GlitchSir@lemmy.world 1 point 2 years ago I think you missed a memo. Exceptions are bad and errors as values are in… I’ll have Harold forward it to you permalink fedilink source parent [–] ennemi@hexbear.net 11 points 2 years ago* The language was designed to be as simple as possible, as to not confuse the developers at Google. I know this sounds like something I made up in bad faith, but it's really not. The key point here is our programmers are Googlers, they’re not researchers. They’re typically, fairly young, fresh out of school, probably learned Java, maybe learned C or C++, probably learned Python. They’re not capable of understanding a brilliant language but we want to use them to build good software. So, the language that we give them has to be easy for them to understand and easy to adopt. – Rob Pike "It must be familiar, roughly C-like. Programmers working at Google are early in their careers and are most familiar with procedural languages, particularly from the C family. The need to get programmers productive quickly in a new language means that the language cannot be too radical. – Rob Pike The infamous if err != nil blocks are a consequence of building the language around tuples (as opposed to, say, sum types like in Rust) and treating errors as values like in C. Rob Pike attempts to explain why it's not a big deal here. permalink fedilink source parent [–] silent_water@hexbear.net 6 points 2 years ago a desperate fear of modular code that provides sound and safe abstractions over common patterns. that the language failed to learn from Java and was eventually forced to add generics anyway - a lesson from 2004 - says everything worth saying about the language. permalink fedilink source parent [+] Draces@lemm.ee 1 point 2 years ago* (last edited 2 years ago) [deleted] permalink fedilink source parent [–] vox@sopuli.xyz 1 point 2 years ago btw lua handles error in exactly the same way permalink fedilink source parent
[–] devfuuu@lemmy.world 33 points 2 years ago (1 child) People are scared of monads and think this is better. permalink fedilink source parent hideshow 2 child comments replies: [–] serenity@lemmy.world 7 points 2 years ago (3 children) My brain is too smooth to imagine a solution to this using monads. Mind sharing what you got with the class? permalink fedilink source parent hideshow 6 child comments replies: [–] nick@campfyre.nickwebster.dev 12 points 2 years ago* (1 child) Having a Result[T, Err] monad that could represent either the data from a successful operation or an error. This can be generalised to the Either[A, B] monad too. permalink fedilink source parent hideshow 2 child comments replies: [–] serenity@lemmy.world 2 points 2 years ago* (3 children) Either[A, B] monad Wait, that's all monads are? some generic class Either ? permalink fedilink source parent hideshow 6 child comments replies: [–] oessessnex@programming.dev 11 points 2 years ago* (last edited 2 years ago) Nope. Monads enable you to redefine how statements work. Let's say you have a program and use an Error[T] data type which can either be Ok {Value: T} or Error: var a = new Ok {Value = 1}; var b = foo(); return new Ok {Value = (a + b)}; Each statement has the following form: var a = expr; rest You first evaluate the "expr" part and bind/store the result in variable a, and evaluate the "rest" of the program. You could represent the same thing using an anonymous function you evaluate right away: (a => rest)(expr); In a normal statement you just pass the result of "expr" to the function directly. The monad allows you to redefine that part. You instead write: bind((a => rest), expr); Here "bind" redefines how the result of expr is passed to the anonymous function. If you implement bind as: B bind(Func[A, B] f, A result_expr) { return f(result_expr); } Then you get normal statements. If you implement bind as: Error[B] bind(Func[A, Error[B]] f, Error[A] result_expr) { switch (result_expr) { case Ok { Value: var a}: return f(a); case Error: return Error; } } You get statements with error handling. So in an above example if the result of foo() is Error, the result of the statement is Error and the rest of the program is not evaluated. Otherwise, if the result of foo() is Ok {Value = 3}, you pass 3 to the rest of the program and you get a final result Ok {Value = 4}. So the whole idea is that you hide the if Error part by redefining how the statements are interpreted. permalink fedilink source parent [–] barsoap@lemm.ee 4 points 2 years ago* (last edited 2 years ago) "Some generic class" with specific methods and laws, Monads are an algebraic structure and you want those laws included same as if you enable some type to use + you want to have a 0 somewhere and x + 0 == x to hold. Like "foo" + "" == "foo" in the case of strings, just as an example. In Rust, Result and Option actually are monads. Let's take Option as example: pure x is Some(x) a >>= b is a.and_then(b) Then we have: Left identity: Some(x).and_then(f) ≡ f(x) Right identity: x.and_then(Some) ≡ x Associativity: m.and_then(g).and_then(h) ≡ m.and_then(|x| g(x).and_then(h)) Why those laws? Because following them avoids surprises like x + 0 /= x. Rust's type system isn't powerful enough to have a Monad trait (lack of HKTs) hence why you can't write code that works with any type that implements that kind of interface. Result names >>= and_then, just like Option does so the code reads the same but you'll have to choose between Option or Result in the type signature, the code can't be properly generic over it. permalink fedilink source parent [–] m_f@midwest.social 3 points 2 years ago This is the best explanation I've ever seen of monads: https://www.adit.io/posts/2013-04-17-functors,_applicatives,_and_monads_in_pictures.html For some reason, you'll find a lot of really bad explanations of monads, like "programmable semi-colons". Ignore those, and check out the link. permalink fedilink source parent [–] psilocybin@discuss.tchncs.de 5 points 2 years ago* (last edited 2 years ago) Someone else and not an expert. But Maybe types are implemented with Monads, Maybe is a common monad. Its how rust does error handling for example, you have to test a return value for "something or nothing" but you can pass the monadic value and handle the error later, in go you have to handle the error explicitly (almost) all the time. permalink fedilink source parent [–] Nevoic@lemmy.world 2 points 2 years ago* (last edited 2 years ago) Here's an example (first in Haskell then in Go), lets say you have some types/functions: type Possible a = Either String a data User = User { name :: String, age :: Int } validateName :: String -> Possible String validateAge :: Int -> Possible Int then you can make mkValidUser :: String -> Int -> Possible User mkValidUser name age = do validatedName ← validateName name validatedAge ← validateAge age pure $ User validatedName validatedAge for some reason <- in lemmy shows up as <- inside code blocks, so I used the left arrow unicode in the above instead in Go you'd have these (no Possible type alias, Go can't do generic type aliases yet, there's an open issue for it) type User struct { Name string; Age int } func validateName(name string) (string, error) func validateAge(age int) (int, error) and with them you'd make: func mkValidUser(name string, age int) (*User, error) { validatedName, err = validateName(name) if err != nil { return nil, err } validatedAge, err = validateAge(age) if err != nil { return nil, err } return User(Name: validatedName, Age: validatedAge), nil } In the Haskell, the fact that Either is a monad is saving you from a lot of boilerplate. You don't have to explicitly handle the Left/error case, if any of the Eithers end up being a Left value then it'll correctly "short-circuit" and the function will evaluate to that Left value. Without using the fact that it's a functor/monad (e.g you have no access to fmap/>>=/do syntax), you'd end up with code that has a similar amount of boilerplate to the Go code (notice we have to handle each Left case now): mkValidUser :: String -> Int -> Possible User mkValidUser name age = case (validatedName name, validateAge age) of (Left nameErr, _) => Left nameErr (_, Left ageErr) => Left ageErr (Right validatedName, Right validatedAge) => Right $ User validatedName validatedAge permalink fedilink source parent
[–] serenity@lemmy.world 7 points 2 years ago (3 children) My brain is too smooth to imagine a solution to this using monads. Mind sharing what you got with the class? permalink fedilink source parent hideshow 6 child comments replies: [–] nick@campfyre.nickwebster.dev 12 points 2 years ago* (1 child) Having a Result[T, Err] monad that could represent either the data from a successful operation or an error. This can be generalised to the Either[A, B] monad too. permalink fedilink source parent hideshow 2 child comments replies: [–] serenity@lemmy.world 2 points 2 years ago* (3 children) Either[A, B] monad Wait, that's all monads are? some generic class Either ? permalink fedilink source parent hideshow 6 child comments replies: [–] oessessnex@programming.dev 11 points 2 years ago* (last edited 2 years ago) Nope. Monads enable you to redefine how statements work. Let's say you have a program and use an Error[T] data type which can either be Ok {Value: T} or Error: var a = new Ok {Value = 1}; var b = foo(); return new Ok {Value = (a + b)}; Each statement has the following form: var a = expr; rest You first evaluate the "expr" part and bind/store the result in variable a, and evaluate the "rest" of the program. You could represent the same thing using an anonymous function you evaluate right away: (a => rest)(expr); In a normal statement you just pass the result of "expr" to the function directly. The monad allows you to redefine that part. You instead write: bind((a => rest), expr); Here "bind" redefines how the result of expr is passed to the anonymous function. If you implement bind as: B bind(Func[A, B] f, A result_expr) { return f(result_expr); } Then you get normal statements. If you implement bind as: Error[B] bind(Func[A, Error[B]] f, Error[A] result_expr) { switch (result_expr) { case Ok { Value: var a}: return f(a); case Error: return Error; } } You get statements with error handling. So in an above example if the result of foo() is Error, the result of the statement is Error and the rest of the program is not evaluated. Otherwise, if the result of foo() is Ok {Value = 3}, you pass 3 to the rest of the program and you get a final result Ok {Value = 4}. So the whole idea is that you hide the if Error part by redefining how the statements are interpreted. permalink fedilink source parent [–] barsoap@lemm.ee 4 points 2 years ago* (last edited 2 years ago) "Some generic class" with specific methods and laws, Monads are an algebraic structure and you want those laws included same as if you enable some type to use + you want to have a 0 somewhere and x + 0 == x to hold. Like "foo" + "" == "foo" in the case of strings, just as an example. In Rust, Result and Option actually are monads. Let's take Option as example: pure x is Some(x) a >>= b is a.and_then(b) Then we have: Left identity: Some(x).and_then(f) ≡ f(x) Right identity: x.and_then(Some) ≡ x Associativity: m.and_then(g).and_then(h) ≡ m.and_then(|x| g(x).and_then(h)) Why those laws? Because following them avoids surprises like x + 0 /= x. Rust's type system isn't powerful enough to have a Monad trait (lack of HKTs) hence why you can't write code that works with any type that implements that kind of interface. Result names >>= and_then, just like Option does so the code reads the same but you'll have to choose between Option or Result in the type signature, the code can't be properly generic over it. permalink fedilink source parent [–] m_f@midwest.social 3 points 2 years ago This is the best explanation I've ever seen of monads: https://www.adit.io/posts/2013-04-17-functors,_applicatives,_and_monads_in_pictures.html For some reason, you'll find a lot of really bad explanations of monads, like "programmable semi-colons". Ignore those, and check out the link. permalink fedilink source parent [–] psilocybin@discuss.tchncs.de 5 points 2 years ago* (last edited 2 years ago) Someone else and not an expert. But Maybe types are implemented with Monads, Maybe is a common monad. Its how rust does error handling for example, you have to test a return value for "something or nothing" but you can pass the monadic value and handle the error later, in go you have to handle the error explicitly (almost) all the time. permalink fedilink source parent [–] Nevoic@lemmy.world 2 points 2 years ago* (last edited 2 years ago) Here's an example (first in Haskell then in Go), lets say you have some types/functions: type Possible a = Either String a data User = User { name :: String, age :: Int } validateName :: String -> Possible String validateAge :: Int -> Possible Int then you can make mkValidUser :: String -> Int -> Possible User mkValidUser name age = do validatedName ← validateName name validatedAge ← validateAge age pure $ User validatedName validatedAge for some reason <- in lemmy shows up as <- inside code blocks, so I used the left arrow unicode in the above instead in Go you'd have these (no Possible type alias, Go can't do generic type aliases yet, there's an open issue for it) type User struct { Name string; Age int } func validateName(name string) (string, error) func validateAge(age int) (int, error) and with them you'd make: func mkValidUser(name string, age int) (*User, error) { validatedName, err = validateName(name) if err != nil { return nil, err } validatedAge, err = validateAge(age) if err != nil { return nil, err } return User(Name: validatedName, Age: validatedAge), nil } In the Haskell, the fact that Either is a monad is saving you from a lot of boilerplate. You don't have to explicitly handle the Left/error case, if any of the Eithers end up being a Left value then it'll correctly "short-circuit" and the function will evaluate to that Left value. Without using the fact that it's a functor/monad (e.g you have no access to fmap/>>=/do syntax), you'd end up with code that has a similar amount of boilerplate to the Go code (notice we have to handle each Left case now): mkValidUser :: String -> Int -> Possible User mkValidUser name age = case (validatedName name, validateAge age) of (Left nameErr, _) => Left nameErr (_, Left ageErr) => Left ageErr (Right validatedName, Right validatedAge) => Right $ User validatedName validatedAge permalink fedilink source parent
[–] nick@campfyre.nickwebster.dev 12 points 2 years ago* (1 child) Having a Result[T, Err] monad that could represent either the data from a successful operation or an error. This can be generalised to the Either[A, B] monad too. permalink fedilink source parent hideshow 2 child comments replies: [–] serenity@lemmy.world 2 points 2 years ago* (3 children) Either[A, B] monad Wait, that's all monads are? some generic class Either ? permalink fedilink source parent hideshow 6 child comments replies: [–] oessessnex@programming.dev 11 points 2 years ago* (last edited 2 years ago) Nope. Monads enable you to redefine how statements work. Let's say you have a program and use an Error[T] data type which can either be Ok {Value: T} or Error: var a = new Ok {Value = 1}; var b = foo(); return new Ok {Value = (a + b)}; Each statement has the following form: var a = expr; rest You first evaluate the "expr" part and bind/store the result in variable a, and evaluate the "rest" of the program. You could represent the same thing using an anonymous function you evaluate right away: (a => rest)(expr); In a normal statement you just pass the result of "expr" to the function directly. The monad allows you to redefine that part. You instead write: bind((a => rest), expr); Here "bind" redefines how the result of expr is passed to the anonymous function. If you implement bind as: B bind(Func[A, B] f, A result_expr) { return f(result_expr); } Then you get normal statements. If you implement bind as: Error[B] bind(Func[A, Error[B]] f, Error[A] result_expr) { switch (result_expr) { case Ok { Value: var a}: return f(a); case Error: return Error; } } You get statements with error handling. So in an above example if the result of foo() is Error, the result of the statement is Error and the rest of the program is not evaluated. Otherwise, if the result of foo() is Ok {Value = 3}, you pass 3 to the rest of the program and you get a final result Ok {Value = 4}. So the whole idea is that you hide the if Error part by redefining how the statements are interpreted. permalink fedilink source parent [–] barsoap@lemm.ee 4 points 2 years ago* (last edited 2 years ago) "Some generic class" with specific methods and laws, Monads are an algebraic structure and you want those laws included same as if you enable some type to use + you want to have a 0 somewhere and x + 0 == x to hold. Like "foo" + "" == "foo" in the case of strings, just as an example. In Rust, Result and Option actually are monads. Let's take Option as example: pure x is Some(x) a >>= b is a.and_then(b) Then we have: Left identity: Some(x).and_then(f) ≡ f(x) Right identity: x.and_then(Some) ≡ x Associativity: m.and_then(g).and_then(h) ≡ m.and_then(|x| g(x).and_then(h)) Why those laws? Because following them avoids surprises like x + 0 /= x. Rust's type system isn't powerful enough to have a Monad trait (lack of HKTs) hence why you can't write code that works with any type that implements that kind of interface. Result names >>= and_then, just like Option does so the code reads the same but you'll have to choose between Option or Result in the type signature, the code can't be properly generic over it. permalink fedilink source parent [–] m_f@midwest.social 3 points 2 years ago This is the best explanation I've ever seen of monads: https://www.adit.io/posts/2013-04-17-functors,_applicatives,_and_monads_in_pictures.html For some reason, you'll find a lot of really bad explanations of monads, like "programmable semi-colons". Ignore those, and check out the link. permalink fedilink source parent
[–] serenity@lemmy.world 2 points 2 years ago* (3 children) Either[A, B] monad Wait, that's all monads are? some generic class Either ? permalink fedilink source parent hideshow 6 child comments replies: [–] oessessnex@programming.dev 11 points 2 years ago* (last edited 2 years ago) Nope. Monads enable you to redefine how statements work. Let's say you have a program and use an Error[T] data type which can either be Ok {Value: T} or Error: var a = new Ok {Value = 1}; var b = foo(); return new Ok {Value = (a + b)}; Each statement has the following form: var a = expr; rest You first evaluate the "expr" part and bind/store the result in variable a, and evaluate the "rest" of the program. You could represent the same thing using an anonymous function you evaluate right away: (a => rest)(expr); In a normal statement you just pass the result of "expr" to the function directly. The monad allows you to redefine that part. You instead write: bind((a => rest), expr); Here "bind" redefines how the result of expr is passed to the anonymous function. If you implement bind as: B bind(Func[A, B] f, A result_expr) { return f(result_expr); } Then you get normal statements. If you implement bind as: Error[B] bind(Func[A, Error[B]] f, Error[A] result_expr) { switch (result_expr) { case Ok { Value: var a}: return f(a); case Error: return Error; } } You get statements with error handling. So in an above example if the result of foo() is Error, the result of the statement is Error and the rest of the program is not evaluated. Otherwise, if the result of foo() is Ok {Value = 3}, you pass 3 to the rest of the program and you get a final result Ok {Value = 4}. So the whole idea is that you hide the if Error part by redefining how the statements are interpreted. permalink fedilink source parent [–] barsoap@lemm.ee 4 points 2 years ago* (last edited 2 years ago) "Some generic class" with specific methods and laws, Monads are an algebraic structure and you want those laws included same as if you enable some type to use + you want to have a 0 somewhere and x + 0 == x to hold. Like "foo" + "" == "foo" in the case of strings, just as an example. In Rust, Result and Option actually are monads. Let's take Option as example: pure x is Some(x) a >>= b is a.and_then(b) Then we have: Left identity: Some(x).and_then(f) ≡ f(x) Right identity: x.and_then(Some) ≡ x Associativity: m.and_then(g).and_then(h) ≡ m.and_then(|x| g(x).and_then(h)) Why those laws? Because following them avoids surprises like x + 0 /= x. Rust's type system isn't powerful enough to have a Monad trait (lack of HKTs) hence why you can't write code that works with any type that implements that kind of interface. Result names >>= and_then, just like Option does so the code reads the same but you'll have to choose between Option or Result in the type signature, the code can't be properly generic over it. permalink fedilink source parent [–] m_f@midwest.social 3 points 2 years ago This is the best explanation I've ever seen of monads: https://www.adit.io/posts/2013-04-17-functors,_applicatives,_and_monads_in_pictures.html For some reason, you'll find a lot of really bad explanations of monads, like "programmable semi-colons". Ignore those, and check out the link. permalink fedilink source parent
[–] oessessnex@programming.dev 11 points 2 years ago* (last edited 2 years ago) Nope. Monads enable you to redefine how statements work. Let's say you have a program and use an Error[T] data type which can either be Ok {Value: T} or Error: var a = new Ok {Value = 1}; var b = foo(); return new Ok {Value = (a + b)}; Each statement has the following form: var a = expr; rest You first evaluate the "expr" part and bind/store the result in variable a, and evaluate the "rest" of the program. You could represent the same thing using an anonymous function you evaluate right away: (a => rest)(expr); In a normal statement you just pass the result of "expr" to the function directly. The monad allows you to redefine that part. You instead write: bind((a => rest), expr); Here "bind" redefines how the result of expr is passed to the anonymous function. If you implement bind as: B bind(Func[A, B] f, A result_expr) { return f(result_expr); } Then you get normal statements. If you implement bind as: Error[B] bind(Func[A, Error[B]] f, Error[A] result_expr) { switch (result_expr) { case Ok { Value: var a}: return f(a); case Error: return Error; } } You get statements with error handling. So in an above example if the result of foo() is Error, the result of the statement is Error and the rest of the program is not evaluated. Otherwise, if the result of foo() is Ok {Value = 3}, you pass 3 to the rest of the program and you get a final result Ok {Value = 4}. So the whole idea is that you hide the if Error part by redefining how the statements are interpreted. permalink fedilink source parent
[–] barsoap@lemm.ee 4 points 2 years ago* (last edited 2 years ago) "Some generic class" with specific methods and laws, Monads are an algebraic structure and you want those laws included same as if you enable some type to use + you want to have a 0 somewhere and x + 0 == x to hold. Like "foo" + "" == "foo" in the case of strings, just as an example. In Rust, Result and Option actually are monads. Let's take Option as example: pure x is Some(x) a >>= b is a.and_then(b) Then we have: Left identity: Some(x).and_then(f) ≡ f(x) Right identity: x.and_then(Some) ≡ x Associativity: m.and_then(g).and_then(h) ≡ m.and_then(|x| g(x).and_then(h)) Why those laws? Because following them avoids surprises like x + 0 /= x. Rust's type system isn't powerful enough to have a Monad trait (lack of HKTs) hence why you can't write code that works with any type that implements that kind of interface. Result names >>= and_then, just like Option does so the code reads the same but you'll have to choose between Option or Result in the type signature, the code can't be properly generic over it. permalink fedilink source parent
[–] m_f@midwest.social 3 points 2 years ago This is the best explanation I've ever seen of monads: https://www.adit.io/posts/2013-04-17-functors,_applicatives,_and_monads_in_pictures.html For some reason, you'll find a lot of really bad explanations of monads, like "programmable semi-colons". Ignore those, and check out the link. permalink fedilink source parent
[–] psilocybin@discuss.tchncs.de 5 points 2 years ago* (last edited 2 years ago) Someone else and not an expert. But Maybe types are implemented with Monads, Maybe is a common monad. Its how rust does error handling for example, you have to test a return value for "something or nothing" but you can pass the monadic value and handle the error later, in go you have to handle the error explicitly (almost) all the time. permalink fedilink source parent
[–] Nevoic@lemmy.world 2 points 2 years ago* (last edited 2 years ago) Here's an example (first in Haskell then in Go), lets say you have some types/functions: type Possible a = Either String a data User = User { name :: String, age :: Int } validateName :: String -> Possible String validateAge :: Int -> Possible Int then you can make mkValidUser :: String -> Int -> Possible User mkValidUser name age = do validatedName ← validateName name validatedAge ← validateAge age pure $ User validatedName validatedAge for some reason <- in lemmy shows up as <- inside code blocks, so I used the left arrow unicode in the above instead in Go you'd have these (no Possible type alias, Go can't do generic type aliases yet, there's an open issue for it) type User struct { Name string; Age int } func validateName(name string) (string, error) func validateAge(age int) (int, error) and with them you'd make: func mkValidUser(name string, age int) (*User, error) { validatedName, err = validateName(name) if err != nil { return nil, err } validatedAge, err = validateAge(age) if err != nil { return nil, err } return User(Name: validatedName, Age: validatedAge), nil } In the Haskell, the fact that Either is a monad is saving you from a lot of boilerplate. You don't have to explicitly handle the Left/error case, if any of the Eithers end up being a Left value then it'll correctly "short-circuit" and the function will evaluate to that Left value. Without using the fact that it's a functor/monad (e.g you have no access to fmap/>>=/do syntax), you'd end up with code that has a similar amount of boilerplate to the Go code (notice we have to handle each Left case now): mkValidUser :: String -> Int -> Possible User mkValidUser name age = case (validatedName name, validateAge age) of (Left nameErr, _) => Left nameErr (_, Left ageErr) => Left ageErr (Right validatedName, Right validatedAge) => Right $ User validatedName validatedAge permalink fedilink source parent
[–] arc@lemm.ee 20 points 2 years ago (1 child) Swift and Rust have a far more elegant solution. Swift has a pseudo throw / try-catch, while Rust has a Result<> and if you want to throw it up the chain you can use a ? notation instead of cluttering the code with error checking. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 6 points 2 years ago (3 children) The exception handling question mark, spelled ? and abbreviated and pronounced eh?, is a half-arsed copy of monadic error handling. Rust devs really wanted the syntax without introducing HKTs, and admittedly you can't do foo()?.bar()?.baz()? in Haskell so it's only theoretical purity which is half-arsed, not ergonomics. permalink fedilink source parent hideshow 6 child comments replies: [–] m_f@midwest.social 1 point 2 years ago (1 child) It's not a half-arsed copy, it's borrowing a limited subset of HKT for a language with very different goals. Haskell can afford a lot of luxuries that Rust can't. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago It's a specialised syntax transformation that has nothing to do with HKTs, or the type system in general. Also HKTs aren't off the table it's just that their theory isn't exactly trivial in face of the rest of Rust's type system but we already have GATs. It actually wouldn't be hard writing a macro implementing do-notation that desugars to and_then calls on a particular type to get some kind of generic code (though of course monomorphised), but of course that would be circumventing the type system. Anyhow my point stands that how Rust currently does it is imitating all that Haskell goodness on a practical everyday coding level but without having (yet) to solve the hard problem of how to do it without special-cased syntax sugar. With proper monads we e.g. wouldn't need to have separate syntax for async and ? permalink fedilink source parent [–] Nevoic@lemmy.world 1 point 2 years ago* (1 child) Note: Lemmy code blocks don't play nice with some symbols, specifically < and & in the following code examples This isn't a language level issue really though, Haskell can be equally ergonomic. The weird thing about ?. is that it's actually overloaded, it can mean: call a function on A? that returns B? call a function on A? that returns B you'd end up with B? in either case Say you have these functions toInt :: String -> Maybe Int double :: Int -> Int isValid :: Int -> Maybe Int and you want to construct the following using these 3 functions fn :: Maybe String -> Maybe Int in a Rust-type syntax, you'd call str?.toInt()?.double()?.isValid() in Haskell you'd have two different operators here str >>= toInt <&> double >>= isValid however you can define this type class class Chainable f a b fb where (?.) :: f a -> (a -> fb) -> f b instance Functor f => Chainable f a b b where (?.) = (<&>) instance Monad m => Chainable m a b (m b) where (?.) = (>>=) and then get roughly the same syntax as rust without introducing a new language feature str ?. toInt ?. double ?. isValid though this is more general than just Maybes (it works with any functor/monad), and maybe you wouldn't want it to be. In that case you'd do this class Chainable a b fb where (?.) :: Maybe a -> (a -> fb) -> Maybe b instance Chainable a b b where (?.) = (<&>) instance Chainable a b (Maybe b) where (?.) = (>>=) restricting it to only maybes could also theoretically help type inference. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago* (last edited 2 years ago) I was thinking along the lines of "you can't easily get at the wrapped type". To get at b instead of Maybe b you need to either use do-notation or lambdas (which do-notation is supposed to eliminate because they're awkward in a monadic context) whereas Rust will gladly hand you that b in the middle of an expression, and doesn't force you to name the point. Or to give a concrete example, if foo()? {...} is rather awkward in Haskell, you end up writing things like foo x y = bar >>= baz x y where baz x y True = x baz x y False = y , though of course baz is completely generic and can be factored out. I think I called it "cap" in my Haskell days, for "consequent-alternative-predicate". Flattening Functors and Monads syntax-wise is neat but it's not getting you all the way. But it's the Haskell way: Instead of macros, use tons upon tons of trivial functions :) permalink fedilink source parent [–] arc@lemm.ee 0 points 2 years ago You can say it's half-arsed if you like, but it's still vastly more convenient to write than if err != nil all over the place permalink fedilink source parent
[–] barsoap@lemm.ee 6 points 2 years ago (3 children) The exception handling question mark, spelled ? and abbreviated and pronounced eh?, is a half-arsed copy of monadic error handling. Rust devs really wanted the syntax without introducing HKTs, and admittedly you can't do foo()?.bar()?.baz()? in Haskell so it's only theoretical purity which is half-arsed, not ergonomics. permalink fedilink source parent hideshow 6 child comments replies: [–] m_f@midwest.social 1 point 2 years ago (1 child) It's not a half-arsed copy, it's borrowing a limited subset of HKT for a language with very different goals. Haskell can afford a lot of luxuries that Rust can't. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago It's a specialised syntax transformation that has nothing to do with HKTs, or the type system in general. Also HKTs aren't off the table it's just that their theory isn't exactly trivial in face of the rest of Rust's type system but we already have GATs. It actually wouldn't be hard writing a macro implementing do-notation that desugars to and_then calls on a particular type to get some kind of generic code (though of course monomorphised), but of course that would be circumventing the type system. Anyhow my point stands that how Rust currently does it is imitating all that Haskell goodness on a practical everyday coding level but without having (yet) to solve the hard problem of how to do it without special-cased syntax sugar. With proper monads we e.g. wouldn't need to have separate syntax for async and ? permalink fedilink source parent [–] Nevoic@lemmy.world 1 point 2 years ago* (1 child) Note: Lemmy code blocks don't play nice with some symbols, specifically < and & in the following code examples This isn't a language level issue really though, Haskell can be equally ergonomic. The weird thing about ?. is that it's actually overloaded, it can mean: call a function on A? that returns B? call a function on A? that returns B you'd end up with B? in either case Say you have these functions toInt :: String -> Maybe Int double :: Int -> Int isValid :: Int -> Maybe Int and you want to construct the following using these 3 functions fn :: Maybe String -> Maybe Int in a Rust-type syntax, you'd call str?.toInt()?.double()?.isValid() in Haskell you'd have two different operators here str >>= toInt <&> double >>= isValid however you can define this type class class Chainable f a b fb where (?.) :: f a -> (a -> fb) -> f b instance Functor f => Chainable f a b b where (?.) = (<&>) instance Monad m => Chainable m a b (m b) where (?.) = (>>=) and then get roughly the same syntax as rust without introducing a new language feature str ?. toInt ?. double ?. isValid though this is more general than just Maybes (it works with any functor/monad), and maybe you wouldn't want it to be. In that case you'd do this class Chainable a b fb where (?.) :: Maybe a -> (a -> fb) -> Maybe b instance Chainable a b b where (?.) = (<&>) instance Chainable a b (Maybe b) where (?.) = (>>=) restricting it to only maybes could also theoretically help type inference. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago* (last edited 2 years ago) I was thinking along the lines of "you can't easily get at the wrapped type". To get at b instead of Maybe b you need to either use do-notation or lambdas (which do-notation is supposed to eliminate because they're awkward in a monadic context) whereas Rust will gladly hand you that b in the middle of an expression, and doesn't force you to name the point. Or to give a concrete example, if foo()? {...} is rather awkward in Haskell, you end up writing things like foo x y = bar >>= baz x y where baz x y True = x baz x y False = y , though of course baz is completely generic and can be factored out. I think I called it "cap" in my Haskell days, for "consequent-alternative-predicate". Flattening Functors and Monads syntax-wise is neat but it's not getting you all the way. But it's the Haskell way: Instead of macros, use tons upon tons of trivial functions :) permalink fedilink source parent [–] arc@lemm.ee 0 points 2 years ago You can say it's half-arsed if you like, but it's still vastly more convenient to write than if err != nil all over the place permalink fedilink source parent
[–] m_f@midwest.social 1 point 2 years ago (1 child) It's not a half-arsed copy, it's borrowing a limited subset of HKT for a language with very different goals. Haskell can afford a lot of luxuries that Rust can't. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago It's a specialised syntax transformation that has nothing to do with HKTs, or the type system in general. Also HKTs aren't off the table it's just that their theory isn't exactly trivial in face of the rest of Rust's type system but we already have GATs. It actually wouldn't be hard writing a macro implementing do-notation that desugars to and_then calls on a particular type to get some kind of generic code (though of course monomorphised), but of course that would be circumventing the type system. Anyhow my point stands that how Rust currently does it is imitating all that Haskell goodness on a practical everyday coding level but without having (yet) to solve the hard problem of how to do it without special-cased syntax sugar. With proper monads we e.g. wouldn't need to have separate syntax for async and ? permalink fedilink source parent
[–] barsoap@lemm.ee 1 point 2 years ago It's a specialised syntax transformation that has nothing to do with HKTs, or the type system in general. Also HKTs aren't off the table it's just that their theory isn't exactly trivial in face of the rest of Rust's type system but we already have GATs. It actually wouldn't be hard writing a macro implementing do-notation that desugars to and_then calls on a particular type to get some kind of generic code (though of course monomorphised), but of course that would be circumventing the type system. Anyhow my point stands that how Rust currently does it is imitating all that Haskell goodness on a practical everyday coding level but without having (yet) to solve the hard problem of how to do it without special-cased syntax sugar. With proper monads we e.g. wouldn't need to have separate syntax for async and ? permalink fedilink source parent
[–] Nevoic@lemmy.world 1 point 2 years ago* (1 child) Note: Lemmy code blocks don't play nice with some symbols, specifically < and & in the following code examples This isn't a language level issue really though, Haskell can be equally ergonomic. The weird thing about ?. is that it's actually overloaded, it can mean: call a function on A? that returns B? call a function on A? that returns B you'd end up with B? in either case Say you have these functions toInt :: String -> Maybe Int double :: Int -> Int isValid :: Int -> Maybe Int and you want to construct the following using these 3 functions fn :: Maybe String -> Maybe Int in a Rust-type syntax, you'd call str?.toInt()?.double()?.isValid() in Haskell you'd have two different operators here str >>= toInt <&> double >>= isValid however you can define this type class class Chainable f a b fb where (?.) :: f a -> (a -> fb) -> f b instance Functor f => Chainable f a b b where (?.) = (<&>) instance Monad m => Chainable m a b (m b) where (?.) = (>>=) and then get roughly the same syntax as rust without introducing a new language feature str ?. toInt ?. double ?. isValid though this is more general than just Maybes (it works with any functor/monad), and maybe you wouldn't want it to be. In that case you'd do this class Chainable a b fb where (?.) :: Maybe a -> (a -> fb) -> Maybe b instance Chainable a b b where (?.) = (<&>) instance Chainable a b (Maybe b) where (?.) = (>>=) restricting it to only maybes could also theoretically help type inference. permalink fedilink source parent hideshow 2 child comments replies: [–] barsoap@lemm.ee 1 point 2 years ago* (last edited 2 years ago) I was thinking along the lines of "you can't easily get at the wrapped type". To get at b instead of Maybe b you need to either use do-notation or lambdas (which do-notation is supposed to eliminate because they're awkward in a monadic context) whereas Rust will gladly hand you that b in the middle of an expression, and doesn't force you to name the point. Or to give a concrete example, if foo()? {...} is rather awkward in Haskell, you end up writing things like foo x y = bar >>= baz x y where baz x y True = x baz x y False = y , though of course baz is completely generic and can be factored out. I think I called it "cap" in my Haskell days, for "consequent-alternative-predicate". Flattening Functors and Monads syntax-wise is neat but it's not getting you all the way. But it's the Haskell way: Instead of macros, use tons upon tons of trivial functions :) permalink fedilink source parent
[–] barsoap@lemm.ee 1 point 2 years ago* (last edited 2 years ago) I was thinking along the lines of "you can't easily get at the wrapped type". To get at b instead of Maybe b you need to either use do-notation or lambdas (which do-notation is supposed to eliminate because they're awkward in a monadic context) whereas Rust will gladly hand you that b in the middle of an expression, and doesn't force you to name the point. Or to give a concrete example, if foo()? {...} is rather awkward in Haskell, you end up writing things like foo x y = bar >>= baz x y where baz x y True = x baz x y False = y , though of course baz is completely generic and can be factored out. I think I called it "cap" in my Haskell days, for "consequent-alternative-predicate". Flattening Functors and Monads syntax-wise is neat but it's not getting you all the way. But it's the Haskell way: Instead of macros, use tons upon tons of trivial functions :) permalink fedilink source parent
[–] arc@lemm.ee 0 points 2 years ago You can say it's half-arsed if you like, but it's still vastly more convenient to write than if err != nil all over the place permalink fedilink source parent
[–] christophski@feddit.uk 7 points 2 years ago (4 children) Can anybody explain the rationale behind this? permalink fedilink source parent hideshow 8 child comments replies: [–] fkn@lemmy.world 14 points 2 years ago (2 children) Exceptions don't exists and ask errors must be handled at every level. It's infuriating. permalink fedilink source parent hideshow 4 child comments replies: [–] planish@sh.itjust.works 4 points 2 years ago I actually kind of like the error handling. Code should explain why something was a problem, not just where it was a problem. You get a huge string of "couldn't foobar the baz: target baz was not greebleable: no greeble provider named fizzbuzz", and while the strings are long as hell they are much better explanations for a problem than a stack trace is. permalink fedilink source parent [–] msage@programming.dev -2 points 2 years ago (1 child) Hahaha, fuck no, I've dealt with exception-less code enough in my life, kthxbye permalink fedilink source parent hideshow 2 child comments replies: [–] GlitchSir@lemmy.world 1 point 2 years ago I think you missed a memo. Exceptions are bad and errors as values are in… I’ll have Harold forward it to you permalink fedilink source parent [–] ennemi@hexbear.net 11 points 2 years ago* The language was designed to be as simple as possible, as to not confuse the developers at Google. I know this sounds like something I made up in bad faith, but it's really not. The key point here is our programmers are Googlers, they’re not researchers. They’re typically, fairly young, fresh out of school, probably learned Java, maybe learned C or C++, probably learned Python. They’re not capable of understanding a brilliant language but we want to use them to build good software. So, the language that we give them has to be easy for them to understand and easy to adopt. – Rob Pike "It must be familiar, roughly C-like. Programmers working at Google are early in their careers and are most familiar with procedural languages, particularly from the C family. The need to get programmers productive quickly in a new language means that the language cannot be too radical. – Rob Pike The infamous if err != nil blocks are a consequence of building the language around tuples (as opposed to, say, sum types like in Rust) and treating errors as values like in C. Rob Pike attempts to explain why it's not a big deal here. permalink fedilink source parent [–] silent_water@hexbear.net 6 points 2 years ago a desperate fear of modular code that provides sound and safe abstractions over common patterns. that the language failed to learn from Java and was eventually forced to add generics anyway - a lesson from 2004 - says everything worth saying about the language. permalink fedilink source parent [+] Draces@lemm.ee 1 point 2 years ago* (last edited 2 years ago) [deleted] permalink fedilink source parent
[–] fkn@lemmy.world 14 points 2 years ago (2 children) Exceptions don't exists and ask errors must be handled at every level. It's infuriating. permalink fedilink source parent hideshow 4 child comments replies: [–] planish@sh.itjust.works 4 points 2 years ago I actually kind of like the error handling. Code should explain why something was a problem, not just where it was a problem. You get a huge string of "couldn't foobar the baz: target baz was not greebleable: no greeble provider named fizzbuzz", and while the strings are long as hell they are much better explanations for a problem than a stack trace is. permalink fedilink source parent [–] msage@programming.dev -2 points 2 years ago (1 child) Hahaha, fuck no, I've dealt with exception-less code enough in my life, kthxbye permalink fedilink source parent hideshow 2 child comments replies: [–] GlitchSir@lemmy.world 1 point 2 years ago I think you missed a memo. Exceptions are bad and errors as values are in… I’ll have Harold forward it to you permalink fedilink source parent
[–] planish@sh.itjust.works 4 points 2 years ago I actually kind of like the error handling. Code should explain why something was a problem, not just where it was a problem. You get a huge string of "couldn't foobar the baz: target baz was not greebleable: no greeble provider named fizzbuzz", and while the strings are long as hell they are much better explanations for a problem than a stack trace is. permalink fedilink source parent
[–] msage@programming.dev -2 points 2 years ago (1 child) Hahaha, fuck no, I've dealt with exception-less code enough in my life, kthxbye permalink fedilink source parent hideshow 2 child comments replies: [–] GlitchSir@lemmy.world 1 point 2 years ago I think you missed a memo. Exceptions are bad and errors as values are in… I’ll have Harold forward it to you permalink fedilink source parent
[–] GlitchSir@lemmy.world 1 point 2 years ago I think you missed a memo. Exceptions are bad and errors as values are in… I’ll have Harold forward it to you permalink fedilink source parent
[–] ennemi@hexbear.net 11 points 2 years ago* The language was designed to be as simple as possible, as to not confuse the developers at Google. I know this sounds like something I made up in bad faith, but it's really not. The key point here is our programmers are Googlers, they’re not researchers. They’re typically, fairly young, fresh out of school, probably learned Java, maybe learned C or C++, probably learned Python. They’re not capable of understanding a brilliant language but we want to use them to build good software. So, the language that we give them has to be easy for them to understand and easy to adopt. – Rob Pike "It must be familiar, roughly C-like. Programmers working at Google are early in their careers and are most familiar with procedural languages, particularly from the C family. The need to get programmers productive quickly in a new language means that the language cannot be too radical. – Rob Pike The infamous if err != nil blocks are a consequence of building the language around tuples (as opposed to, say, sum types like in Rust) and treating errors as values like in C. Rob Pike attempts to explain why it's not a big deal here. permalink fedilink source parent
[–] silent_water@hexbear.net 6 points 2 years ago a desperate fear of modular code that provides sound and safe abstractions over common patterns. that the language failed to learn from Java and was eventually forced to add generics anyway - a lesson from 2004 - says everything worth saying about the language. permalink fedilink source parent
[+] Draces@lemm.ee 1 point 2 years ago* (last edited 2 years ago) [deleted] permalink fedilink source parent
[–] vox@sopuli.xyz 1 point 2 years ago btw lua handles error in exactly the same way permalink fedilink source parent