What's weirder is that the bottom two are 6 feef apart
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What dimensional space are the people arranging themselves in?
But seriously, this reminds me of a time at my former (FAANG) employer where HR sent out a 40-minute video about not being an asshole and avoiding lawsuits.
12 minutes or so in, they say "as the number of people in a group increases, the number of potential 1:1 interactions increases exponentially." I thought "actually n(n-1)/2 but whatever", and finished the video intending to get on with my life.
My inbox was FULL of engineers who were irate. "HR have proven themselves to be fools!" "I expect the company to never ask me to waste my time on their bullshit again." "Once again non-technical people talking out their asses."
HR sent a global apology for the error, asked everybody to not watch the video while they fixed it, and released a patched version the next day.
HR should have replied with a "this was a test on how not to be an asshole and you've all failed. You must take the whole training again"
Wow, cool HR. Why did the engineers send their complaints to your inbox though?
Reply all
"Reply all" button should only be available if you have completed the training on not using it for every email, and you have to renew it twice a year
In any discussion around Reply All I always think of https://redd.it/420oan
and also the podcast
Ah I see.
I'm a little sad nobody has done the correct math and it's been too long for me to do it off the top of my head lol.
A^2+B^2=C^2? What distance are the diagonals if the sides are 6' apart?
6x6 + 6x6 = sqrt72 = 8.49' !
I did it bois. Ty calculator for sqrt72...
Now do the conversion factor from feef to feet!
Now, what's the length of the sides if the diagonals are 6ft?
Thats easy.
6 * 6 = 36
36 = a² + b²
Lets assume a = b
So a² = 18 = b²
a = b = 4,2426406871
It is SO HORRIBLE Stephen Hawking got on his feet.
how much is a "feef"
Let's do the math. Let's name the points A B C D, where A and D are separated by 6 feef, and all other point pairs by 6 feet. There fore, ABC and BCD are equilateral triangles of side length 6 feet. This leaves two possibilities for the distance between A and D: either they are the same point, or their distance is twice the height of an equilateral triangle with 6 feet side. Since A and D are clearly distinct, we'll go with the latter. That makes the distance AD to be equal to 6 feet times the square root of three, giving a value of sqrt(3) feet for one feef.
Join us, the order of enlightenment! (not a cult btw 😉)
Why? The diagram is from above and they're shifted in 3 dimensions. Now draw that. I'm not asking. DRAW IT!
If the 6 feet is from head to head, couldn't you flip two people upside down?
I did the math the diagonal distance is ~8.5Ft
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