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[–] 11 points 5 months ago* (1 child)

No, OP is correct, && only continues on exit 0. || For anything but zero, ; just chains another command.

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  • [–] 2 points 5 months ago (1 child)

    Ah yes you're right, had to look it up to see for myself. It's weird because i remember specifically changing some of my &&s for ; instead because i wanted it to not continue if exit wasn't zero, but i must've misread it at the time. Time to change it back i guess lol.

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  • [–] 3 points 5 months ago

    It makes more sense if you think of semicolons like other programming languages like Java and C use it.

    foo();
    bar();
    

    But those languages allow foo(); bar(); as well. Then && works like a normal short circuited expression (with side effects).

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