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[–] 33 points 2 years ago (2 children)

Doesn't, the binary pattern 10101010 dosen't exists on that number, for example.

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  • [–] 5 points 2 years ago (1 child)
  • [–] 14 points 2 years ago

    No, because you can't mathematically guarantee that pi contains long strings of predetermined patterns.

    The 1.101001000100001... example by the other user was just that - an example. Their number is infinite, but never contains a 2. Pi is also infinite, but does it contain the number e to 100 digits of precision? Maybe. Maybe not. The point is, we don't know and we can't prove it either way (except finding it by accident).

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