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Statically Typed Functional Programming with Python 3.12 (wickstrom.tech)
submitted 2 years ago by to c/python@programming.dev
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Neato

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[–] 3 points 2 years ago* (1 child)

You're still limited by lambda expressions though. And in general the language is still statement based, not expression based. You can't do a = if foo then x else y type things (except for the one-off and backwards x if foo else y; they were so close!).

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  • [–] 2 points 2 years ago (1 child)

    "a = x if foo else y" is a perfectly cromulent statement!

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  • [–] 2 points 2 years ago (1 child)

    It's not. In functional languages there's no special case like this. All if-elses are expressions. It's far superior. For example how do you do this with Python's if-else expression?

    let x = if foo {
  let y = bar();
  baz();
  y
} else {
  z
}
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  • [–] 1 point 2 years ago (1 child)

    x = foo(y:=bar(), baz(), y) or z should work assuming foo bar and baz are functions being called?

    if this is setting y to the effect of bar() + running baz after, then:

    x = [bar(), baz()][0] or z

    might work

    and if you need y to be defined for later use:

    x = [(y:=bar()), baz()][0] or z

    but thats from memory, not sure if that will even run as written.

    if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.
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