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Do you see Black and Blue, or White and Gold? (lemmy.world)
submitted 3 years ago* (last edited 3 years ago) by [M] to c/antiquememesroadshow@lemmy.world
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[–] 12 points 3 years ago* (last edited 3 years ago) (2 children)

https://imagecolorpicker.com/en for those seeing white and gold. Also the screen you're looking at it on matters so much.

Edit: I did find a neat bug with DarkReader on though. It reads the white pixels as black with the magnifier on the right. Even turning off it's still pretty blue and white... Apparently it actually pulls the color judging by what your screen shows though... which is pretty neat all considering. The crosshair is on the large white empty space to the right of the large black stripe in the middle.

DarkReader off: https://i.imgur.com/0ofjl8W.png

DarkReader on: https://i.imgur.com/OpcDGCH.png

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  • [–] 11 points 3 years ago (1 child)

    So I tried this and even https://colors.artyclick.com/color-name-finder/ but it will find only brown/gold and light blue/blue/white depends where you focus it on. This image itself contains no black pixels simple as it is.

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  • [–] 8 points 3 years ago* (1 child)

    Seems to me a color picker confirms white and gold. Although the white has a bluish tint, some areas don't even have that, and are light grey. There is no doubt the gold (black) is different tones between brown and yellow, which is the RGB you'd expect for a gold color.

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  • [–] 4 points 3 years ago (1 child)

    I don't get the same at all. Can you send a screenshot? This was the easy hack to show the image is literally Blue and Gold/Brown. The rest is the entire point of the optical illusion.

    https://i.imgur.com/iJBt2Mj.png

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  • [–] -2 points 3 years ago

    I just saved your image and loaded it into GIMP, and the correct value for the brownish color shown as selected is RGB(256): 78,66,39. (decimal) The same value for both the selection in the read square, and the one left of the RGBA value that is wrong. Brown and yellow colors are dominated by red and green, the RGB value shown in your picture can't possibly match the color shown as the selected color.

    The value shown in your software is wrong.

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