▲ 789 ▼ soak and jump hump (feddit.de) submitted 2 years ago by sexy_peach@feddit.de to c/memes@lemmy.ml 151 comments fedilink hide all child comments
[–] driving_crooner@lemmy.eco.br 24 points 2 years ago* (last edited 2 years ago) (3 children) Did you mean oron? permalink fedilink source parent hideshow 6 child comments replies: [–] NoIWontPickaName@kbin.social 9 points 2 years ago (1 child) I can’t tell if that is a purposeful typo or not. permalink fedilink source parent hideshow 2 child comments replies: [–] sus@programming.dev 5 points 2 years ago* mormon - 5*n = Oro permalink fedilink source parent [–] _danny@lemmy.world 4 points 2 years ago* (1 child) Technically it'd need to be: mormon / 2m = oron permalink fedilink source parent hideshow 2 child comments replies: [–] driving_crooner@lemmy.eco.br 4 points 2 years ago (2 children) A word isn't a product of letters, that would made mormon = nomorm, but an ordered set, where the subtract operation gives you the first set without any element also found on the second set (in set notation A-B = A-(A intersection B) permalink fedilink source parent hideshow 4 child comments replies: [–] _danny@lemmy.world 2 points 2 years ago You're right, that would be more technically correct. permalink fedilink source parent [–] themusicman@lemmy.world 1 point 2 years ago* If words are an ordered set, then mormon = morn Words are a base 27 integer. (mormon - mon) / a000 + on = moron permalink fedilink source parent [–] Jorgelino@lemmy.ml 2 points 2 years ago Perhaps... permalink fedilink source parent
[–] NoIWontPickaName@kbin.social 9 points 2 years ago (1 child) I can’t tell if that is a purposeful typo or not. permalink fedilink source parent hideshow 2 child comments replies: [–] sus@programming.dev 5 points 2 years ago* mormon - 5*n = Oro permalink fedilink source parent
[–] _danny@lemmy.world 4 points 2 years ago* (1 child) Technically it'd need to be: mormon / 2m = oron permalink fedilink source parent hideshow 2 child comments replies: [–] driving_crooner@lemmy.eco.br 4 points 2 years ago (2 children) A word isn't a product of letters, that would made mormon = nomorm, but an ordered set, where the subtract operation gives you the first set without any element also found on the second set (in set notation A-B = A-(A intersection B) permalink fedilink source parent hideshow 4 child comments replies: [–] _danny@lemmy.world 2 points 2 years ago You're right, that would be more technically correct. permalink fedilink source parent [–] themusicman@lemmy.world 1 point 2 years ago* If words are an ordered set, then mormon = morn Words are a base 27 integer. (mormon - mon) / a000 + on = moron permalink fedilink source parent
[–] driving_crooner@lemmy.eco.br 4 points 2 years ago (2 children) A word isn't a product of letters, that would made mormon = nomorm, but an ordered set, where the subtract operation gives you the first set without any element also found on the second set (in set notation A-B = A-(A intersection B) permalink fedilink source parent hideshow 4 child comments replies: [–] _danny@lemmy.world 2 points 2 years ago You're right, that would be more technically correct. permalink fedilink source parent [–] themusicman@lemmy.world 1 point 2 years ago* If words are an ordered set, then mormon = morn Words are a base 27 integer. (mormon - mon) / a000 + on = moron permalink fedilink source parent
[–] _danny@lemmy.world 2 points 2 years ago You're right, that would be more technically correct. permalink fedilink source parent
[–] themusicman@lemmy.world 1 point 2 years ago* If words are an ordered set, then mormon = morn Words are a base 27 integer. (mormon - mon) / a000 + on = moron permalink fedilink source parent